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/></td> <td> <p style="font-size:1.4em;">@30=870F8O 1J548=5==KE 0F89</p> </td> <td> <p> <span style="font-size:2em;">CCPR</span>/C/CHE/CO/4</p> </td> </tr> <tr> <td> </td> <td> <p style="font-weight:bold;font-size:1.7em;">564C=0@>4=K9 ?0:B > 3@0640=A:8E 8 ?>;8B8G5A:8E ?@020E</p> </td> <td> <p>Distr.: General</p> <p>22 August 2017</p> <p>Russian</p> <p>Original: French</p> </td> </tr> </table> <div class="content"> <p style="font-weight:bold;font-size:1.2em;">><8B5B ?> ?@020< G5;>25:0</p> <h2 style="font-weight:bold;">0:;NG8B5;L=K5 70<5G0=8O ?> G5B25@B><C ?5@8>48G5A:><C 4>:;04C (259F0@88 *</h2> <p>1.><8B5B @0AA<>B@5; G5B25@BK9 ?5@8>48G5A:89 4>:;04 (259F0@88 (CCPR/C/CHE/4) =0 A2>8E 3374-< 8 3375-< 70A540=8OE (A<. 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35 (2014) > A2>1>45 8 ;8G=>9 =5?@8:>A=>25==>AB8.</span> </p> <h3>">@3>2;O ;N4L<8</h3> <p>40.><8B5B A C4>2;5B2>@5=85< >B<5G05B C:07 > ?@54C?@5645=88 ?@5ABC?;5=89, A2O70==KE A B>@3>2;59 ;N4L<8, :>B>@K9 2ABC?8; 2 A8;C 1 O=20@O 2014 3>40, A>740=85 >>@48=0F8>==>3> 1N@> ?> 1>@L15 A B>@3>2;59 ;N4L<8 8 =570:>==K< 22>7>< <83@0=B>2, 0 B0:65 CB25@645=85  ?CABL 8 A >?>740=85< 8 ?>A;5 B@5E;5B=59 ?0C7K  2B>@>3> =0F8>=0;L=>3> ?;0=0 459AB289 ?> 1>@L15 A B>@3>2;59 ;N4L<8 =0 2017 2020 3>4K. <5AB5 A B5< >= >15A?>:>5= A>>1I5=8O<8 > =54>AB0B>G=KE >1J5<0E :04@>2KE 8 D8=0=A>2KE @5AC@A>2, 2K45;O5<KE 4;O >ACI5AB2;5=8O 40==>3> ?;0=0. ><8B5B B0:65 2K@0605B >15A?>:>5==>ABL ?> ?>2>4C B@C4=>AB59, 2>7=8:0NI8E ?@8 2KO2;5=88 65@B2 B>@3>2;8 87-70 >BACBAB28O C=8D8F8@>20==>3> ?@>F5AA0 2> 2A5E :0=B>=0E 8 =54>AB0B>G=>9 ?>43>B>2:8 A>B@C4=8:>2 ?>;8F88 8 AC451=KE >@30=>2 2 MB>9 >1;0AB8 (AB0BLO 8).</p> <p>41.<span style="font-weight:bold;">>AC40@AB2C-CG0AB=8:C A;54C5B : 0) ?@8=OBL <5@K : B><C, GB>1K A;54CNI89 =0F8>=0;L=K9 ?;0= 459AB289 1K; ?>43>B>2;5= 2 CAB0=>2;5==K9 A@>:, 0 4;O F5;59 53> MDD5:B82=>3> >ACI5AB2;5=8O 1K;8 2K45;5=K =04;560I85 :04@>2K5 8 D8=0=A>2K5 @5AC@AK ; b) 225AB8 C=8D8F8@>20==CN 8 A>3;0A>20==CN <564C :0=B>=0<8 ?@>F54C@C 2KO2;5=8O 65@B2 B>@3>2;8 ;N4L<8 ; 8 c) ?@>2>48BL ?@>3@0<<K ?> ?>2KH5=8N >A254><;5==>AB8 8 ?>43>B>2:5 A>B@C4=8:>2 ?>;8F88 8 AC451=KE >@30=>2 2 MB>9 >1;0AB8.</span> </p> <h3>0?@5B =0 AB@>8B5;LAB2> <8=0@5B>2</h3> <p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p> <p style="font-weight:bold;">43. >AC40@AB2C-CG0AB=8:C A;54C5B ?@8=OBL <5@K ?> ?@5>4>;5=8N 70?@5B0 AB@>8B5;LAB20 =>2KE <8=0@5B>2, 2 G0AB=>AB8 ?5@5A<>B@5BL ?C=:B 3 AB0BL8 72 >=AB8BCF88.</p> <h3>!2>1>40 A>25AB8 8 @5;838>7=KE C15645=89</h3> <p>44.><8B5B ?@825BAB2C5B <5@K, ?@8=OBK5 3>AC40@AB2><-CG0AB=8:>< 4;O A>459AB28O <56:>=D5AA8>=0;L=><C 480;>3C. <5AB5 A B5< >= 2K@0605B >15A?>:>5==>ABL 2 A2O78 A ?>2A5<5AB=K< 22545=85< ?@028;, :0A0NI8EAO H:>;L=>3> :>=B5:AB0 8;8 =>H5=8O >4564K 2 >1I5AB25==KE <5AB0E, ?@54CA<0B@820NI8E A>>B25BAB2CNI85 HB@0DK 8 3;02=K< >1@07>< 70B@03820NI8E, :0: ?@54AB02;O5BAO, <CAC;L<0= (AB0BL8 18, 26 8 27).</p> <p style="font-weight:bold;">45. >AC40@AB2C-CG0AB=8:C A;54C5B ?5@5A<>B@5BL A2>5 70:>=>40B5;LAB2> 8 2A5 ?@028;0, 70B@03820NI85 3;02=K< >1@07>< <CAC;L<0=, 2 A25B5 A2>8E >1O70B5;LAB2 ?> 0:BC.</p> <h3>5@K A;565=8O 8 ?@02> =0 =5?@8:>A=>25==>ABL G0AB=>9 687=8</h3> <p>46.@8=8<0O : A2545=8N <5@K ?> 30@0=B8@>20=8N ?@02 G5;>25:0, 2:;NG5==K5 2 $545@0;L=K9 70:>= > @07254K20B5;L=>9 45OB5;L=>AB8 >B 25 A5=BO1@O 2016 3>40, ><8B5B >15A?>:>5= B5<, GB> A>3;0A=> 40==><C 70:>=C @07254K20B5;L=K5 A;C61K >=D545@0F88 =045;ONBAO ?>;=><>G8O<8 ?> ?@>2545=8N 25AL<0 8=B@C782=>3> =01;N45=8O ?>4 ?@54;>3>< =5G5B:> AD>@<C;8@>20==KE 7040G, :0:-B> 70I8BK C?><8=05<KE 2 AB0BL5 3 =0F8>=0;L=KE 8=B5@5A>2. ><8B5B B0:65 2K@0605B >15A?>:>5==>ABL ?> ?>2>4C B>3>, GB> ?@545;L=K5 A@>:8 E@0=5=8O 40==KE =5 CAB0=>2;5=K (AB0BLO 17).</p> <p style="font-weight:bold;">47. >AC40@AB2C-CG0AB=8:C A;54C5B ?@8=OBL 2A5 =5>1E>48<K5 <5@K : B><C, GB>1K <5@>?@8OB8O ?> A;565=8N ?@>2>48;8AL 2 A>>B25BAB288 A 53> >1O70B5;LAB20<8, 2KB5:0NI8<8 87 ?>;>65=89 0:B0, 2 >A>15==>AB8 AB0BL8 17.  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